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End Function Private Function Release(This As LightEmpty) As Long With This cRefs = cRefs - 1 Release = cRefs If cRefs = 0 Then 'Add object specific cleanup here 'Free the memory Don't step over CoTaskMemFree 'in the debugger because the memory associated 'with the This parameter is being freed Now is 'a good time to hit F5 or Ctrl-Shift-F8 CoTaskMemFree VarPtr(This) End If End With End Function 'Helper function Private Function FuncAddr(ByVal pfn As Long) As Long FuncAddr = pfn End Function There are several things you should notice in this baseline code The first strange thing is that the vtable is declared as a structure rather than as a fixedsize array As mentioned in 2, the data for a fixed-size array is actually heap allocated, so it must be freed during the teardown If you happen to have a lightweight object at module level that still points to the vtable, your application is very, very dead if it happens to teardown after its vtable By declaring the vtables as shown above, you have guaranteed that the vtables will be around longer than any object in the project Another thing you should notice in the code is that you deal with allocated memory as a raw pointer only when the object is first created and when it is being freed At all points in between, you can look at the LightEmpty structure directly The three IUnknown vtable functions, and all other vtable functions shown in the chapter, have a first parameter typed "This As <Struct>" As the parameter name indicates, the This parameter is the typed memory associated with the current object In VB and C + + classes, the this/Me parameter is implied as part of the language Although you don't see it as a parameter, it is

An ISP typically has one or more blocks of IP addresses that have been assigned to it by one of IANA s regional registries. The ISP might use one block of addresses for its residential broadband customers, another block for a college campus, and another block for a larger enterprise customer. The difficult part of the ISP s task is to split up and assign just enough of these addresses to each customer enough to anticipate and allow future growth, but not so many that the ISP runs out of addresses. The ISP can allocate one block right after another so that the address numbering is consecutive without gaps, or intentionally leave gaps between the blocks for future growth. By sizing the blocks appropriately, multiple smaller blocks can later be grouped together as one single larger block. Maximizing block size helps minimize the number of unusable addresses and thus improves the efficiency of the ISP s overall address space. This exercise looks at one example with just a few of the typical constraints on utilization of the address space. Objective In this exercise, you will design and implement an IP network addressing scheme that satisfies multiple addressing constraints and supports communications between multiple routers. Figure 5.32 provides the example network topology. This is a paper exercise. Validation You will know you have succeeded by verifying your answers with the solutions provided at the end of this appendix.

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15

Figure 5.32 A simplified diagram shows how an ISP connects to multiple sites of two different enterprises.

High Performance Cluster Computing (HPCC) High Availability (HA)

Two enterprises, A and B, are connected to a central Tier 2 ISP. A.1 and A.2 are two of Enterprise A s locations connected to the Tier 2 ISP, and B.1 and B.2 are two of Enterprise B s locations connected to the same Tier 2. The ISP has a public IP addressing space of 138.120.16.0/20. Enterprises A and B lease their IP addressing from their ISP. Enterprise A requires an IP addressing scheme that can scale to at most 30 nodes in location A.1 and 60 nodes in location A.2. Enterprise B requires an IP addressing scheme with at most 90 nodes in location B.1 and less than 300 nodes in location B.2. The ISP can only lease 500 IP addresses, distributed between the two enterprises, and will utilize the last part of its assigned subnetwork to connect to both the enterprises. Your tasks are to: 1. Extract a 500 host subnetwork from the last part of the ISP IP network address of 138.120.16.0/20. 2. Divide the resulting subnetwork into unequal subnetworks satisfying all the site requirements for each of the enterprise locations.

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The subnetworks assigned to each location do not have to be a single aggregate block so long as they satisfy the number of addresses required.

Virtualization HW Assist Virtualization SW Supported Virtualized I/0 (networking and storage) capabilities

3. wherever possible, optimize address spaces among enterprise locations. Use the following table to help you complete your solution: Hint: for this example, you can start by dividing the assigned ISP IP subnetwork into equal blocks that best satisfy the smallest requirement. Once the blocks have been assigned, combine as many smaller blocks as possible into aggregate blocks while obeying the rules for aggregation. Note that the best fit solution may mean that not all blocks can be aggregated.

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